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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: D C Pandey Q frm rotational motion 2
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feynmann (2236)

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Olaaa!! Perrrfect answer. 404  [512 rates]

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I think the vector approach would be more simple to understand .


Suppose , wrt any origin chosen , the P.V. of the first and second particles be r1 and r2 .


Given that r1-r2= + a .............( 1) ( a is a scalar which depends on time ) ( p and -p their respective momentum )


Now denote the angular momentum of any particle by L


So , L1= r1 X p


L2= r2 X( -p) )


So L1+ L2 = ( r1-r2) X p = ( d+ a p ) Xp = d Xp = a constant ( independent of time )

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