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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2008 09:22:47 IST
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by conservation of energy
at horizontal
1/2(10mgl)=mgl+1/2mv^2
so,
v=rt(8gl)
now
mv^2/l=T
T=8mg
at higest point
1/2(10mgl)=2mgl+1/2mv^2
v=rt(6gl)
here
mg+T=mv^2/l
T=7mg
similarly
at 60 deg
1/2(10mgl)=(1-cos 60)mgl+1/2mv^2
v=3gl
now,
mg cos60-T=mv^2/l
T=5mg/2
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even a stopped clock is right twice a day |
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