IIT JEE , AIEEE Forum - Physics , Mechanics

harimanjunath

THE SIMPLEST SOLUTION:
Since there are no external forces ALONG THE HORIZONTAL,there is no acceleration of com along horiz. either.Hence velocity is purely vertical.Let length of rod be l

let the height of com from ground at any instant be h.

therefore sin@=2h/l (from congruency and trig.)

but h=l/2-{g*[square(t)]}/2

let t square be tsquare.
finaly sin@=2h/l=2*(l/2-1/2g tsquare)/l=1-g*tsquare/l
hence tsquare=l*(1-sin@)/g
therefore t=root of......
hence v=0 + gt=...root(gL(1-sin@)).Simple math

0

Ask & Discuss Questions with Community & Experts