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[Post New]1 Jul 2008 22:49:05 IST
    Subject: resistance
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atul_sinha89 (46)

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consider the minor and major arc as two parallel resistors, lert radius of the ring be r ,then

resistance per unit length (RP)= R / 2(pi)r
resistance of minor arc = [RP]*r(theta)

resistance of major arc = [RP]* r[2(pi)-(theta)]


calculate the eqivalent resistance for parallel resistors of above resistance..

ans=(a)
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