|
|
Put cos 2x = 1 / t
So, dx = dt / ( 2t2 . sin 2x)
so,   cos2x/sinx =  dt / ( 2t2 . 2sin2x) *  t * cosx
= dt / 2 * t(t-1) t+1
Now put t + 1 = p2
So, cos2x/sinx = 2* dp / (p2 - 1)*( p2 - 2 )
= 2* dp / ( p2 - 2 ) - 2* dp / ( p2 - 1 )
Now these integrals can be easily intergated and thus we are done by resubstituting the values of p.
Cheers !!!!!!!!!!!!
|
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
620
2
