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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Jul 2008 13:27:30 IST
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Your question is not clear,If it is
(1-tanx)(1+tanx)(sec2x)+2tan2x=0
then (1-tan2x)/cos2x+2tan2x=0
 sec2x+2tan2x=0
 3tan2x+1=0 which has no solution.
If the question is different,Plz post it clearly.
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
this reply: 5 points
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