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Discussion Response Post to: H.C.Verma chapter magnetic field questio-22 and 27 of the exercise not able to solve.

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anchit saini (4396)

Blazing goIITian

total posts: 1251
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This is what i could make out of the qn ->

The force is towards right

The wire moves from the left end to the right end covering a distance l , during which time B acts on it , thereafter it moves on the floor where friction acts on it , and at a distance x from the strips the wire stops

The energy gained due to B is = Fl = ibB l = mg x

which gives

x= $\frac{ilbB}{\mu mg}$

Impossible To be Impossible is Impossible

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