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[Post New]9 Jul 2008 19:20:59 IST
    Subject: Re:indefinite integral ::rates assured
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allamraju (3422)

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Write the numerator 3+4cosx as

3(cos2x+sin2x)+4cosx=3sin2x+cosx(4+3cosx).

Using this,we write


Now,The integrand is of the form

(sinx)(1/4+3cosx)'+(1/4+3cosx)(sinx)'=[sinx/4+3cosx]' whose integral is (sinx/4+3cosx)+c.Hence answer is option (A).
MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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