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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Jul 2008 18:23:24 IST
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let the velocity b v
now as the stone is dropped it has an initial velocity of 5m/s in the upward direction...
now h=-61.25m
applying -h=ut-1/2gt^2
(g is negative as i have taken the upward direction i.e in the initial direction of the stone's movement..... so the height as well as acceleration due to gravity negative.
another way is to take downward direction positive so u will get the equation as...
h=-ut+1/2gt^2
just fill in the values.. mind u only the values i have already used the signs for them...
61.25= -5u+125
5u=125-61.25=63.75
u=12.75m/s
rate if useful....
n nudge me for any doubts
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