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snail (165)

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Olaaa!! Perrrfect answer. 23  [48 rates]

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It is infinity. I think we can do it like this:




 


Total distance travelled by the particle = time for mirrors to collide * velocity of particle




 


                                                                     =d/2v * 3v = 3d/2




 


 




 


Consider first trip of particle,




 


It will hit the 2nd mirror at a distance = 3/4 *d     (bcause particle vel is 3v and mirror vel is v)




 


By this time both the mirrors have travelled a distance of d/2 together. So remaining distance is d/2 only.




 


Insecond trip it will hit  1st mirror at a distance = 3/4*d/2




 


In third trip distance travelled by particle is = 3/4*d/4




 


In  fourth  trip......................................................= 3/4*d/8  and so on....




 


So the total distance travelled by particle =3/4*d +3/4 *d/2 +3/4 * d/4 + 3/4 * d/8 +.....+....+  ..




 


This is a G.P , a=3/4*d & r= 1/2




 


So the sum =  a(1-rn)/(1-r)




 


                      3/4*d (1-(1/2)n)/(1-1/2) =3d/2 (taken from the above)




 


                                         1-(1/2)n = 1




 


                                             (1/2)n = 0




 


                                             1/2n =0 This is possible only when n= (infinity)


SLOW AND STEADY WINS THE RACE
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