IIT JEE-AIEEE 2012, Entrance Notifications, Study Tips, Engineering Preparation, Practice Test Papers, Experts Advice

Discussion Response Post to: normal reaction

Forum Index -> Mechanics -> View Full Question

Author

Message

Priyesh (1601)

Blazing goIITian

total posts: 1042
Offline

Hi Vish0001

see the question is asking normal reaction exerted by ground on the entire ring and not the normal reaction on a particle of the ring.

now if you consider a particle

N(on particle)=dm(g) + dmw^2r (you have taken as mw^2r)

= dm(g+w^2r)

integrating we get N(on ring)=Mg+ Mw^2r

now this N is considered on the centre of ring i.e centre of mass

(because we have taken r as constant while integrating) therefore since the centre does not rotate therefore N=Mg

Hope you understood

Like 0 people liked this

Free Sign Up!

@ INR 1,995/-