sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

 Moderation Team
Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: Limits
Forum Index -> Differential Calculus -> View Full Question like the article? email it to a friend.  
Author Message
[Post New]29 Mar 2007 16:12:23 IST
    Subject: Re:Limits
[Up]
iitkgp_bipin (5892)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 1004  bad job dude!! I dont approve of this answer! 1  [1442 rates]
iitkgp_bipin's Avatar
total posts: 4084    
offline Offline
Rationalizing numerator and denominator :
 
((x-8) - 1)((x-8) + 1)/((x-8) + 1) = (x - 9 )/((x-8) + 1)
 
(x - 3)(x + 3)/(x + 3) = (x-9)/(x + 3)
 
Hence  
 
[x][0] ((x-8) - 1)/(x - 3) = [x][0]  {(x-9)/(x-9)}{(x + 3)/((x-8) + 1)
 
                                      =  (3+3)/(1+1) = 3
[
Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

 this reply: 10 points  (with 2 Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya