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Discussion Response Post to: shm prob

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Priyesh (1601)

Blazing goIITian

total posts: 1042
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Hi Abhijeet

the general equation is

= Asin(

t +

) ------------------- 1

where theta is angular displacement &

is the phase & omega is angular frequency & A is the amplitude

now in your question since at t=0 the angular displacement is equal to the amplitude therefore sin( omegat +

)=1 (from equation 1) therefore

is equal to pi/2. also omega = 2pi/timeperiod = 2pi/.05 = 40pi

now the general equation becomes

= pi/10sin(

t + pi/2)

=pi/10cos(

t)=pi/10cos(40pi*t)

hope you understood

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