|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 Mar 2007 12:12:10 IST
Accepted Answer [?]
|
|
|
Hi Wisp We know that the ball leaves the stick with a velocity of 10m/s in a direction tangential to the rotation of stick.
f = v/r= 10 rad/s
a = wf2 - w02/2theta
a= 10^2/pi = 31.9 rad/s^2
|
this reply: 7 points
(with 1 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|