sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

 Moderation Team
Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: the circumference of second orbit of H-atom if the wavelength of electron is 5*10-9m
Forum Index -> Physical Chemistry -> View Full Question like the article? email it to a friend.  
Author Message
[Post New]4 Oct 2008 16:22:32 IST
    Subject: Re:the circumference of second orbit of H-atom if the wavelength of electron is 5*10-9m
[Up]
srujana (3264)

Blazing goIITian

Olaaa!! Perrrfect answer. 584  [756 rates]
srujana's Avatar
total posts: 893    
offline Offline

According to de Broglie's theory, the circumference of an orbit is equal to the integral multiples of the wavelength of the electron revolving in it

n \lambda =2 \pi r



(n is the orbit number)



substituting n=2  and \lambda=5\times 10^{-9}



hence, circumference = 1 Angstrom

Hence (3) is the correct option
God has given you one face, and you
make yourself another.
~William Shakespeare

You were born an original. Don't die a copy.
~John Mason
 this reply: 2 points  (with 0 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
 

 Aakash Institute IIT/ AIEEE/ Medical Crash Course
Name  
E-mail  
Phone  
Mobile  
** Hurry. Exclusive goIIT Offer. Limited Seats Only!
available in: New Delhi, Amritsar, Bhatinda, Bokaro, Chandigarj, Dehradun, Guwhati, Hyderabad, Indore, Jaipur, Kanpur, Karnal, Kolkata, Kota, Lucknow, Ludhiana, Mumbai, Noida, Patiala, Patna, Pune, Ranchi, Varanasi
Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Aakash-IITJEE : AIEEE
Aakash-IITJEE : DCE
Aakash-IITJEE : MHTCET
Aakash Institute : AIPMT
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya