E-Store
Kinematics
|
| Forum Index -> Mechanics -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
a) work done = change in kinetic enrgy work done from x = 1m to x =0.5m = integral -k/2x^2dx (x from 1 to .5) = [k/2 * 1/x] = k/2 =>k/2 = 1/2mv^2 => v^2 = k/m =.01/.01 = 1 since intitially particle is at rest & acceleration is towards left hence final velocity is also left hence v = - 1m/sec |
|||||||||||||
"Imagination is more important than knowledge." |
||||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||
Free Sign Up!
Preparing for IIT-JEE ?
Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor
@ INR 1,995/-
For Quick Info
|
|
|
|
|
| 35,229,755 Engineering Questions Attempted |
6,69,530 Visitors Monthly |
79 Engg. Exam Covered |
699 Students Currently Online |
Connect with Us  |
 |
Vriti Communities
Privacy Policy © Vriti 2011