E-Store
LOGIC MAGIC
|
| Forum Index -> Mechanics -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
SIMPLE LOGIC AND NO MAGIC..... Soln - Let us consider total distance d. First of all, we consider the first part of the question. time = d/(2v0) ......1 Second part, next distance =v1t........ 2 and last half distance =V2t ..........3 therefore , v1 t + v2 t = d /2 t = d/[2(v1+ v2 )] Now,finally from 1, 2 & 3 average speed = d/{[d/2v0]+ [d/2(v1+v2)] +[d/2(v1+v2)]} average speed =2v0(v1 + v2 )/[( v1+ v2 ) + 2v0 ]
|
|||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||
Free Sign Up!
Preparing for IIT-JEE ?
Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor
@ INR 1,995/-
For Quick Info
|
|
|
|
|
| 35,229,755 Engineering Questions Attempted |
6,69,530 Visitors Monthly |
79 Engg. Exam Covered |
1241 Students Currently Online |
Connect with Us  |
 |
Vriti Communities
Privacy Policy © Vriti 2011