Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: For <11th Grade
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Hari Shankar (9109)

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That is right.


But, what you can do after noting that x=0 is a solution, is to see that if x>0 (obviously within bounds) then LHS>\sqrt a + \sqrt b + \sqrt c while RHS<\sqrt a + \sqrt b + \sqrt c


The reverse happens if x<0. Hence never the twain shall meet if x \ne 0


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