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![[Post New]](/templates/default/images/icon_minipost_new.gif) 5 Apr 2007 13:35:21 IST
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Frequency f  T1/2 where T is the tension.
Hence f1/f2 = (T1/T2)1/2 (100/81)1/2 = 10/9
Let the frequency of fork be f.
Then f1 - f = 5 and f - f2 = 5
(f + 5)/(f - 5) = 10/9
f = 95 Hz
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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this reply: 5 points
(with 1 
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