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[Post New]28 Dec 2006 11:35:11 IST
    Subject: sum on complex number
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vinu (524)

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Olaaa!! Perrrfect answer. 78  bad job dude!! I dont approve of this answer! 1  [147 rates]
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Hi,namesake.
mul. & div. ur expression by 2^39n;  (^ means  power raised to)
u get , 2^39n[cis 39n {2# / 3}+cis 39n{4# / 3}]
( using prop's, (cis ?)^n=cisn?  ;   cis ?+cis @=cis( ?+@ ) ;)
u' ll ' ve ; 2^39n[cis 39n{2#}]
           =2^39n[(cis 2#)^39n]
           =2^39n[1]
 So, the ans is ....... 2^39n.
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