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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2007 04:44:16 IST
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dU = 0 implies nCvdT = 0 i.e. dT = 0
dQ = dU + dW = dW (since dU=0)
dQ = PdV
Also you have written that dQ = nCpdT but if the process is isothermal, how it can be isobaric(it can be both isobaric and isothermal during phase change when gas become liquid).
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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this reply: 2 points
(with 0 
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