Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Problem [Admin]: Mechanics numerical
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saket_brutus (112)

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5gsin30+4.5=(-5a)--- (a = acceleration)
From this a=(-5.9m/s2)  Put 'a' in v2=u2+2as (v=0,u=6,a= -5.9)
U get s=3.05 m
Increase in PE=5g(s * sin30)= 5*g*3.05*0.5= 76.25 J
 
if i am wrong , please reply.
 

Saket
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