IIT JEE-AIEEE 2012, Entrance Notifications, Study Tips, Engineering Preparation, Practice Test Papers, Experts Advice

Ask iit jee aieee pet cbse icse state board community

Discussion Response Post to: Molarity & Molality

Forum Index -> Physical Chemistry -> View Full Question

Author

Message

10904him (114)

Hot goIITian

total posts: 191
Offline

For molality ---
100 ml of each sol
--> 121.8 gm 30% sol ----121.8 X 70/100 =85.3 gm solvent and 121.8 - 85.3 gm solute =36.5 gm solute = 0.37 mol acid

Similarly

---> 161 gm 70% sol ----161 X 30/100=48.3gm solvent and
161-48.3 =112.7 gm acid =1.15 mol acid
Thus on mixing 100 ml of each solution of 200 ml forms with
1.15 +0.37 =1.52 mol acid

Total mass of solvent = 85.3 + 48.3=133.6 gm

Molality =1.52 / 0.1336 = 11.4 m Ans

Being a genius is 1% luck and 99% perspiration........

Like 0 people liked this

Free Sign Up!

Preparing for IIT-JEE ?

Arihant Revision Package for IIT JEE - Books, Practice Tests + Rank Predictor

@ INR 1,995/-

For Quick Info