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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Apr 2007 23:51:20 IST
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Use - (a2+b2) <= a.sinx + b.cosx <= (a2+b2)
Hence - (32+42) <= 3.sinx + 4.cosx <= (32+42)
-5 <= 3.sinx + 4.cosx <= 5
Now add 5 to each term
0 <= 3.sinx + 4.cosx + 5 <= 10
Hence minimum value is 0 and maximum value is 10.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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this reply: 2 points
(with 0 
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