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Harpreet aka MAX (58)

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  • Let the velocity at initial pt that is the first point is " u " and const accle is "a"


  • then as given S=180m ; t= 6 sec ;


  • by S= ut + 1/2 at2



we have


180 = 6u + 18a


u + 3a = 30---------- (1)


now also using the other thing


We have  v= 45m/s ; t = 6


v = u+at


we have u = 45-6a ----------- (2)


putting value of u in (1) we get a and u


u (velocity at first point )  = 15m/s


a( Accleration) = 5 m /s





Hope u got it .....


Rates plz ....




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