finding inradius of right angled triangle
|
| Forum Index -> Analytical Geometry -> View Full Question |
|
| Author | Message | |||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
|
inradius = (area of triangle)/s where s = (a + b+ c)/2 therefore inradius = 6/6 = 1 In my opinion the inradius has to be 1 maybe the experts would rectify the ans. |
|||||||||||||
"Imagination is more important than knowledge." |
||||||||||||||
| Like 0 people liked this | ||||||||||||||
|
|
||||||||||||||












