hi ishwarya........try dis q like dis............ integral of 0 to n^2 {x} dx " (x - [x]) dx sooo......we get integral of 0 to n^2 x dx - integral of 0 to n^2 [x] dx sooo....solving the 1st term u ll get n^4/2 for the 2nd term......... integral of 0 to n^2 [x] dx split it......u ll get integral of 0 to 1^2 0dx + integral of 1^2 to 2^2 1dx.......nd so onnn till integral of (n-1)^2 to n^2 (n-1)^2 dx soo.........now by simply solving the series u ll get the ans hope u got it thanx
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
101
