hi its a nice q i think the limit does nt exist see by solving.......... lim x ->0 (1-cosx)^1/2 /x lim x->0 (2sin^2 x)^1/2 /x soo.......we get lim x->0 root2 l sinx l /x { dis is the main step....dont forget the mod} sooo LHL is not equal to RHL hence limit does nt exist hope m correct thanx
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