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[Post New]1 Jan 2007 14:24:38 IST
    Subject: Re:photoelectric effect (tough one)
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edison (5135)

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The stopping potential is related to the (maximum) kinetic energy of the ejected electrons by
eV0 = KE max = $\displaystyle{\textstyle\frac{1}{2}}$mv max2.
 
 
Further,
 
KE max = eV0 = hf - $\displaystyle\phi$ = $\displaystyle{\frac{hc}{\lambda}}$ - $\displaystyle\phi$.
 
Here E = Eo sin [1.57*107(ct -x )]
 
so,   = 2 = 1.57*107 c
 
Now find  and substitute the value to find Stopping potential Vo
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