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Avinash_Bhat (665)

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Olaaa!! Perrrfect answer. 111  [166 rates]

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KINEMATICS : 1 DIMENSIONAL
 
 body dropped from height ' h ', it reaches the ground in time ' t ' such that final velocity is ' u '.         n  R
 
At height (h - h/n) from the ground : the velocity is u / n
                                                  : the time taken is t / n   
 
 body dropped from height ' h ' while at the sametime another body vertically projected upwards with a velocity ' u '. these meet after a time of (h / u) at a distance of (g / 2)(h / u)from the top.
 
' n ' balls thrown every second such that, one ball thrown when the previous one reaches its maximum height. Now this max. height = (g / 2n2 )
 
Juggler keeps n balls going with one hand, so that (n-1) balls in air and 1 in hand. Each ball rises to height 'x' so that time for each ball to stay in his hand is : 2(2x/g) / (n-1)   
 
    
 

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