ball vertically thrown up, passes through the same point at times, t1 and t2.

Then : t1 + t2 = 2u / g = total time the ball remains in air ( T ).  

        : t1*t2 = T²

 

body dropped from a height and the time taken to cover successive 1 m distances in the ratio    1 : (2 - 1) : (3 - 2) : (4 - 3) : (5 - 4) : .......

 

body starts from rest and constantly accelerates at 'a' m/s² for time t1 and then retards at 'r' m/s² for time t2, coming to rest. Let t1 + t2 = T Maximum velocity attained = at1 = rt2 = ( arT ) / (a + r). Total diatance covered = (arT² ) / 2(a + r) 

 

                                                 What do you say ??