IIT JEE , AIEEE Forum - Chemistry , Physical Chemistry

malay

This is the explanation:
Let no. of moles of cl-35=x
no. of moles of cl-37=y
total mass present in the system=35x+37y
total no. of moles=x+y
effective molar weight of the mixture(i.e. chlorine)=(35x+37y)/(x+y)
but this is given to be 35.45
hence
35.45=(35x+37y)/(x+y)
1.55y=.45x
y/x=.45/1.55
y/x=9/31

now the two gases are separated.
they are at same temperature, and have same pressure.
pV=nRT
V/n=RT/p
hence V/n is same for both gases
let for cl35, V be V1 and for cl37 it be V2
V1/x=V2/y
V1/V2=x/y
V1/V2=31/9
total volume= V1+V2=V=initial volume of the box
hence
V1/V=31/40
V2/V=9/40

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