|
|
|
|
|
| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Jan 2007 14:04:35 IST
|
|
|
Friends let me write the solution of this problem and also the mistake in the solution provided by rashmi What rashmi has done is that she has taken 3 points and then she draws a plane passing through all those points and then taken 4th point and she says we will find a plane which is equidistant from the plane we have drawn and from the last point ...........................this is correct , but is it exhaustive ......................no definitely not What about those cases in which plane will separate four points , two above it and two below it...................................definitely that case isnt covered , and there is 4C2/2 ways to do this(divided by two because planes will be same in half of the case) , i.e , 3 cases. Total number of possible planes are 7 This is correct because it is exhaustive , means we cannot choose 4 points on same , plane as that will violate their non-coplanarity and 3,1 and 1,3 case are same , and (2,2) case is now covered.
|
life is like red red rose |
this reply: 10 points
(with 2 
in 2 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
|
|
|
|
|