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puneet (3558)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 618  bad job dude!! I dont approve of this answer! 2  [856 rates]

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total posts: 1966    
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hii
let us first try to simplify the expression ...
 
so
(cos5x + cos4x)/(1 - 2cos3x)
= (2cos(9x/2).cos(x/2))/(1 - 2cos3x)
= (2cos(9x/2).cos(x/2))/( 1 - 2.(2cos2(3x/2) - 1) )
= (2cos(9x/2).cos(x/2))/(3 - 4.cos2(3x/2))
= (2.(4.cos3(3x/2) - 3cos(3x/2)).cos(x/2))/(3 - 4.cos2(3x/2))
= -2.cos(3x/2)cos(x/2)
= -( cos2x + cosx )
 
so now the integral is  -sin(2x)/2 - sinx + c
 
cheers
 

Puneet Agrawal
IIT Delhi
 this reply: 5 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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