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C1-C3 ->C1 |x-z y z | |0 x y | |z-x y x | = (x-z) |1 y z | |0 x y | |-1 y x| R1+R3->R1 = (x-z) | 0 2y z+x | | 0 x y | |-1 y x | =(x-z) (-1) (2y2 ?xz -x2) =(x-z) (x2 +xz ?2y2) (NOTE:These are not a broken lines.They are continuous lines for showing the determinant .)
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Moderation Team
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