apply boyl"s law here P1V1=P2V2 LET P1=P V1=V THEN V2 WILL BE 8 TIMES AS THAT OF V1 BCOZ RADIUS IS BECOMING DOUBLE SO P1=8P2 MEANS INITIAL PRESSURE WAS 8 TIMES TO THAT OF FINAL(atmospheric) now assume that lake has 100% water density of water d=10 raise to the power3 kg/m cube now calculate it using P=dgh