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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: A.P, G.P, H.P
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Avinash_Bhat (655)

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Olaaa!! Perrrfect answer. 109  [164 rates]

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1)
 
  and  are the roots of x2 - 3x + a = 0. SO :  +  = 3   = a
 
  and  are the roots of x2 - 12x + b = 0. SO :  +  = 12   = b
 
, , ,  are in G.P. Let  = p ;  = pq ;  = pq2 ;  = pq3
 
ie, p + pq = p(1 + q) = 3 --------- (1)
     pq2 + pq3 = pq2(1 + q) = 12 ---------- (2)
 
Solving (1) and (2) to get q = 2 and p = 1.
 
SO : a = p2q = 2                     &                         b = p2q5 = 32
    
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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