6X^2-35x-6>=0 or,(6x+1)(x-6)>=0 or,X<=(1/6) and x>=6
furthur, cos x>=0.5 or x<=(pie)/3 orx<=1.04(almost) by taking the principal values. frm the numberline answer is X<=(1.04) and x>=6 ie, x belongs to (-infi,1.04)union (6,+infi)
but i am little confused,plz correct me if i am wrong,most probably i am!
Moderation Team
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