That is a simple question Take a point charge q at the center of gaussian sphere of radius r Now according gauss law surface integarl(E.dA)= Q_inside/eplison_zero Since E is constant on the surface of the sphere by symmetry Now we E*(surface integral (dA)) =Q_inside/eplison_zero E *4*pie *r^2 = Q_inside/eplison_o now we have solving for E= Q/(4*pie*eplison_0*r^2) now if we place a test charge q then the electric force experienced by the test cahrge is F = Eq which leds to coulomb's law F = Qqr(unit vector)/(4*pie*eplison_o*r^2)
Moderation Team
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