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[Post New]23 Apr 2007 14:03:27 IST
    Subject: Re:max. value???
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iitkgp_bipin (6498)

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Olaaa!! Perrrfect answer. 1106  bad job dude!! I dont approve of this answer! 1  [1592 rates]
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Let xy = z

a2x4 + b2y4 = c6
a2x4 + b2(z/x)4 = c6
z4 = (a2x8 - c6x4)/b2

Now differentiate both sides wrt x and put dz/dx = 0 for maxima.
You will get x4 = c6/2a2
Putting this in the above equation : y4 = c6/2b2

Hence x4y4 = (c6/2a2)(c6/2b2)

xy = c3/(2ab)1/2

Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

 this reply: 5 points  (with 1 Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
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