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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Jan 2007 13:53:24 IST
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=27^10+7^51
=3^30+7^51
=9^15+7^51
=(10-1)^15+7(49)^25
=(10-1)^15+7(50-1)^25
=just expand and we will get
=an integral multiple of 10- (15c15)-7(25c25)
=an integral multiple of 10-8
=an integral multiple of 10-10 +2
=an integral multiple of 10+2
hence remainder is 2
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