5)a,b,c are in G.P.
Therefore,
b²=ac

ac-b²=0.

Now,
x=(a+b)/2 & y=(b+c)/2

Thus,
(a/x+c/y)-(b/x+b/y)={2a/(a+b)+2c/(b+c)} - {2b/(a+b)+2b/(b+c)}
=(2ab+2ac+2ac+2bc-2ab-2b^2-2b^2-2bc)/
  {(a+b)(b+c)}
=(4ac-4b²)/{(a+b)(b+c)}
=4(ac-b²)/{(a+b)(b+c)}
=0.

PLEAZZZZ RATE IF CORRECT...