ans 1= 1+5

ans 2= a,b,c

ans 3= all x>=4(d)

ans 4=30

ans 5=0

 

soln:

1)max distanxe of z lying on the given circle from i will be along the line throgh i passing through the centre of the circle. from 2 solutions obtained the one which lies on the other side of centre as i,gives the ans.

2)let z1,z2,z3 be the roots,

so c=1,

a=Iz1+z2+z3I<=Iz1I+Iz2I+Iz3I<=3

similarly b<=3

3)posted above

4)if u check for the maximum power of x that u'll get it comes out to b 625

to obtain 615 u have to omit some powers of x while mutiplying the brackets.

u'll have 2 remove (1,9) and (3,7) powers while actually multiplying the term along them.......

this gives 1*9+3*7=30

5)posted above

 

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