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[Post New]25 Apr 2007 17:43:55 IST
    Subject: Re:please solve this...........ABC is a right angled triangle with
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ramya_kapoor (326)

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Olaaa!! Perrrfect answer. 56  [79 rates]
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this is easy......
area=abc/4R
a/sinA=b/sinB=c/sinC=2R
b/sin 90=2*5=10 ie b=10
frm right triangle.....c=
[ ]10^2-6^2.............=8..
thus area=6*10*8/5*4=24...ok
 
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