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rahul_c (188)

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Olaaa!! Perrrfect answer. 32  bad job dude!! I dont approve of this answer! 3  [52 rates]

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RADIUS OF THE FIRST BOHR ORBIT IS 0.53 ANGSTROM =0.53*(10^(-10))
 
BY HEISENBERG'S UNCERTAINITY PROBLEM WE KNOW THAT
 
  p*x >= h/(4(pie))--------(1)
 
  where p= momentum of the electron
        x= uncertainity in the location of Bohr orbit (1%= 10^(-2))
        h= planck's constant (6.62 * 10^(-34)) Js
 
 p can be expressed as m*v
        where m = mass of the electron ( m=9.1*10^(-31)kg)
              v= velocity of the electron
  putting the values in (1) we get  pie=3.14
 
v >=6.62*10^(-34)/[(4* 3.14)*9.1*10^(-31)*0.53*(10^-10)*10^(-2)]  

v >= 1.094 * (10^8) m/s
therefore the least value of velocity is 1.094 * (10^8) m/s  
 
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