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10  (sin 2  k/11+i cos2 k/11)=i (cos 2 k/11-isin2 k/11) ........(1) k=1 let z=(cos 2 /11- isin 2 /11) i.e k=1 z 2=(cos 4 /11- isin 4 /11) =(cos 2 /11- isin 2 /11)2 k=2 hence (1) becomes =i(z+z2+z3+......+z10) =i.z(z10-1)/(z-1) =i(z11-z)/(z-1) z11=1 hence =i(1-z)/(z-1) =i(-1) = -i Rate me if correct
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Moderation Team
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