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neeraj_agarwal_1990 (887)

Blazing goIITian

Olaaa!! Perrrfect answer. 135  [241 rates]

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yup the ans is c...
|z|=1 => z.conj(z)=1 => conj(z) = 1/z...(1)
|z1 + z2 +....+ zn| = | conj(z1+ z2+...........+zn)|=|conj(z1)+....conj(zn)|
Now Put from (1)
 this reply: 10 points  (with Olaaa!! Perrrfect answer.   in 2 votes )   [?]
 
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