sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
Ask iit jee aieee pet cbse icse state board experts Discussion Response Post to: indefinate integrals
Forum Index -> Integral Calculus -> View Full Question like the article? email it to a friend.  
Author Message
edison (4927)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 867  [1163 rates]

edison's Avatar

total posts: 2485    
offline Offline
SINCE,  0 ][1 ] f(x) dx = 1,  [0 ][ 1] xf(dx) = a  &  [0 ][ 1] x2 f(x) dx  a2
therefore, I = [0 ][ 1] (a -x)2f(x) dx is = [0 ][ 1] (a2 - 2ax + x2)f(x) dx
           or I = [0 ][ 1] a2 f(x) dx -2a[0 ][ 1] x f(x) dx + [0 ][ 1] x2f(x) dx
or I = a2 [0 ][ 1] f(x) dx - 2a(a) + a2 = a2.1 - 2a.a + a2
so, I = 0

The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp.
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
 

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya