If the area of the smaller sector be A, then we have
A=1/2 r2 x (x is the central angle)
So area of bigger sector = 3A
=3/2 r2 x
which can be written as 1/2 r2 (3 x )
that is, the angle subtended by major sector = 3x
also being a diameter
x + 3x = 180
=> x=45
thus we knw that angle between a pair of lines is given by
tan X = 2 sqrrt (h2 - ab)
a+b
putting x = 45, we have
1 = 2
((a+b)2-ab) /(a+b) => (a+b) = 2((a+b)2-ab) squaring (a+b)2 = 4(a+b)2-4ab
=> 3(a+b)2-4ab = 0
=> a2+2ab+3b2 = 0
Moderation Team
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