Use L-Hopitals - cos x - sin x - 1/ [1-x] by 3x^2 sin x - cos x - 1/[1-x]^2 by 6x cos x + sin x - 2 / [1-x]^3 by 6 Substitute Values 1 + 0 - 2 by 6 -1 / 6
I May Have Been Wrong......Please Temme If I Am
Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
227
